Chemical Equilibrium

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Question

${XY}_{2} dissociates {XY}_{2} (g) ⇌ XY (g) + Y (g)$ when the initial pressure of XY₂is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction. Assuming that the volume of the system remains unchanged.

Moderate

Solution

Initial P = 600 mm Hg, Final P = 800 mm Hg
Total moles $\propto$ final P.
$\begin{aligned} ∴ P - x + x + x \propto 800 \\ 600 - x + x + x \propto 800 \end{aligned}$
$x = 200 mm Hg$
$K = \frac{x \times x}{P - x} = \frac{200 \times 200}{400} = 100 mm Hg$

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