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‘z’ cannot be directly prepared from its elements conveniently.The best route to prepare ‘z’ is

 x+C+Cl2 600800Ky LiAlH4z. Then x,  y,  z are 

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a
CaO, CaCl2, CaH2
b
BeO,  BeCl2,  BeH2
c
BaO,  BaCl2,  BaH2
d
SrO,  SrCl2,  SrH2

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detailed solution

Correct option is B

BeO+C+Cl2→ 600−800KBeCl2→ LiAlH4BeH2+LiCl+AlCl3

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