‘z’ cannot be directly prepared from its elements conveniently.The best route to prepare ‘z’ is x+C+Cl2→ 600−800Ky→ LiAlH4z. Then x, y, z are

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CaO, CaCl2, CaH2

BeO, BeCl2, BeH2

BaO, BaCl2, BaH2

SrO, SrCl2, SrH2

answer is B.

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Detailed Solution

BeO+C+Cl2→ 600−800KBeCl2→ LiAlH4BeH2+LiCl+AlCl3

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