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Q.

11+ω−11+2ω−12+ω=

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a

ω

b

ω2

c

4

d

0

answer is D.

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Detailed Solution

11+ω−11+2ω−12+ω=(1+2ω)(2+ω)−(1+ω)(2+ω)−(1+ω)(1+2ω)(1+ω)(1+2ω)(2+ω)=0
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11+ω−11+2ω−12+ω=