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(A)1 is always equal to  where A is nth -order square matrix) 

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a
−1nA−1
b
−A−1
c
−1n−1A−1
d
none of these

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detailed solution

Correct option is B

−A−1=adj−A|−A|=−1n−1adj(A)(−1)n|A|=adj(A)−|A|=−A−1


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