α,β are the eccentric angles of the extremities of a focal chord of the ellipse x2/16+y2/9=1 then tan(α/2)tan(β/2)=
7+47−4
-923
5−45+4
87−239
The eccentricity e=1−916=74
Let P(4cosα,3sinα) and Q(4cosβ,3sinβ) be a focalchord of the ellipse passing through the focus at (7,0)
then,
⇒3sinβ4cosβ−7=3sinα4cosα−7⇒sin(α−β)sinα−sinβ=74⇒cos[(α−β)/2]cos[(α+β)/2]=74⇒tanα2tanβ2=7−47+4=23−87−9