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[(a→×b→)×(b→×c→) (b→×c→)×(c→×a→) (c→×a→)×(a→×b→)] is equal to (where a→,b→ and c→ are non-zero non-coplanar vectors)

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a

[a→b→c→]2

b

[a→b→c→]3

c

[a→b→c→]4

d

[a→b→c→]

answer is C.

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Detailed Solution

[(a→×b→)×(b→×c→) (b→×c→)×(c→×a→) (c→×a→)×(a→×b→)]=[[a→b→c→]b→ [a→b→c→]c→ [a→b→c→]⋅a→]=abc3[b→ c→a→]=[a→b→c→]4

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[(a→×b→)×(b→×c→) (b→×c→)×(c→×a→) (c→×a→)×(a→×b→)] is equal to (where a→,b→ and c→ are non-zero non-coplanar vectors)