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In a $△ A B C, a = 2 b$ and $A = 3 B,$ then $A =$

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Correct option is A

We have,a=2b⇒2Rsin⁡A=4Rsin⁡B⇒sin⁡A=2sin⁡B⇒sin⁡3B=2sin⁡B [∵A=3B]⇒3sin⁡B−4sin3⁡B=2sin⁡B⇒sin⁡B−4sin3⁡B=0⇒1−4sin2⁡B=0⇒sin⁡B=12⇒B=π6∴A=3B=π2

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In a △ABC, a=2b and A=3B, then A=

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Ready to Test Your Skills?

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In a $△ A B C, a = 2 b$ and $A = 3 B,$ then $A =$