In ΔABC cosA+cosB+cosC=74 andrR=k4, then k=
1
2
3
4
cosA+cosB+cosC=74⇒1+4sinA2sinB2sinC2=74 if A+B+C=π,then cosA+cosB+cosC=1+4sinA2sinB2sinC2⇒4sinA2sinC2sinB2=34⇒rR=34 ∵4RsinA2sinC2sinB2=r⇒k=3