[a→×b→ c→×d→ e→×f→] is equal to

Let A→=a→×b→,B→=c→×d→ and C→=e→×f→ We know that A→⋅(B→×C→)=B→⋅(C→×A→)=C→⋅(A→×B→)=(a→×b→)⋅[(c→×d→)×(e→×f→)]=(a→×b→)⋅[{(c→×d→)⋅f→}e→−{(c→×d→)⋅e→}f}→=[c→d→f→][a→b→e→]−[c→d→e→][a→b→f→]Similarly, other parts can be obtained.