In △ABC if $$A(0$$,$$0)$$ , internal angle bisector through vertex B is $$x+2y$$−$$5=0$$ and perpendicular bisector of the side AC is $$3x$$−y−$$10=0$$ , then the absolute value of slope of line BC is

Question

In △ABC if $$A(0$$,$$0)$$ , internal angle bisector through vertex B is $$x+2y$$−$$5=0$$ and  perpendicular bisector of the side AC is $$3x$$−y−$$10=0$$ , then the absolute value of slope of  line BC is

Infinity Learn · Accepted Answer

Point C will be image of A in $$3x$$−y−$$10=0x$$−$$03=y$$−$$0$$−$$1=$$−$$2$$−$$1010C=x$$,$$y=6$$,−$$2$$ Image of A in $$x+2y$$−$$5=0$$ lie on BCx−$$01=y$$−$$02=$$−$$2$$−$$55$$    $$($$∵Im⁡age  formula ⁡h−$$x1a=k$$−$$y1b=$$−$$2ax1+by1+ca2+b2x$$,$$y=2$$,$$4$$∴ Slope of BC,$$mBC=6$$−$$4=$$−$$32$$

$In △ A B C if A (0, 0), internal angle bisector through vertex B is x + 2 y - 5 = 0 and$ $perpendicular bisector of the side A C is 3 x - y - 10 = 0, then the absolute value of slope of$ $line B C is$

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In △ABC if A(0,0) , internal angle bisector through vertex B is x+2y−5=0 and perpendicular bisector of the side AC is 3x−y−10=0 , then the absolute value of slope of line BC is

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$In △ A B C if A (0, 0), internal angle bisector through vertex B is x + 2 y - 5 = 0 and$ $perpendicular bisector of the side A C is 3 x - y - 10 = 0, then the absolute value of slope of$ $line B C is$