In a ΔABC,sin4A+sin4B+sin4C=
32+2cosAcosBcosC+12cos2Acos2Bcos2C
2cosAcosBcosC+12cos2Acos2Bcos2C
2cosAcosBcosC+12cos2Acos2B
2cosAcosBcosC+cos2Acos2B
L.H.S =1−cos2A22+1−cos2B22+1−cos2C22
=34+14(cos22A+cos22B+cos22C)
−12(cos2A+cos2B+cos2C)