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Q.

∫cos⁡ec2exexdxx is equal to

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a

−2cotex+C

b

2cotex+C

c

−2cotex+C

d

2cotex+C

answer is A.

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Detailed Solution

Let I=∫cos⁡ec2exexxdx Put ex=y2exxdx=dyI=2∫cos⁡ec2ydy=2(−cot⁡y)+CI=−2cot⁡ex+C
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