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cosec2exexdxx is equal to 

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a
−2cotex+C
b
2cotex+C
c
−2cotex+C
d
2cotex+C

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detailed solution

Correct option is A

Let I=∫cos⁡ec2exexxdx Put ex=y2exxdx=dyI=2∫cos⁡ec2ydy=2(−cot⁡y)+CI=−2cot⁡ex+C


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