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Q.

∫cosecmx  cotx   dx  =

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a

cosecmxm+c

b

−1m−1cosecmx+c

c

−1msinmx+c

d

1msinmx+c

answer is C.

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Detailed Solution

−∫cosecm−1x(−cosecx.cotx) dx           f(x)m−1          =        f|(x)                        =−cosecmxm+c                        =−1msinmx+c
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