First slide
Introduction to integration
Question

cosec2x2005cos2005xdx

Moderate
Solution

 I=(cosx)2005cosec2xdx2005dxcos2005xI=(cosx)2005(cotx)(2005)(cosx)2006(sinx)(cotx)dx2005dxcos2005xI=-cotx(cosx)2005+C

 

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