∫cosecxtanxdx=

I=∫cos⁡ecxtan⁡xdx=∫cos⁡x(sin⁡x)32dx Let sin⁡x=tcos⁡xdx=dt I=∫t−32dt=t1−321−32+C=−2t+C=−2sin⁡x+C Level of question: Moderate