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cosxcox2x1cosxdx=

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a
x+2sinx+c
b
x+2cosx+c
c
x−2cosx+c
d
x−2sinx+c

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detailed solution

Correct option is A

cos⁡x−cos⁡2x=cos⁡x−2cos2⁡x+1=(1−cos⁡x)(1+2cos⁡x)


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(1cosx)cosec2xdx is equal to


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