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$\int \frac{\cos 2 x - \cos 2 θ}{\cos x - \cos θ} d x is equal to$

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2(sin⁡x+xcos⁡θ)+C

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detailed solution

Correct option is A

∫cos⁡2x−cos⁡2θcos⁡x−cos⁡θdθ=∫2cos2⁡x−1−2cos2⁡θ−1cos⁡x−cos⁡θdθ =2∫cos2⁡x−cos2⁡θcos⁡x−cos⁡θdθ=2∫(cos⁡x+cos⁡θ)dθ=2sin⁡x+2xcos⁡θ+C

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∫cos⁡2x−cos⁡2θcos⁡x−cos⁡θdx is equal to

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$\int \frac{\cos 2 x - \cos 2 θ}{\cos x - \cos θ} d x is equal to$