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cos2x-cos2θcosx-cosθdx=

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a
2(sinx+xcosθ)+C
b
2(sinx-xcosθ)+C
c
2(sinx+2xcosθ)+C
d
2(sinx-2xcosθ)+C

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detailed solution

Correct option is A

∫cos2x-cos2θcosx-cosθdx=∫(2cos2x-1)-(2cos2θ-1)cosx-cosθdx=2∫cos2x-cos2θcosx-cosθdx=2∫(cosx+cosθ)+C = 2∫cosxdx+∫cosθ dx  =2(sinx+cosθ. x)+C


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