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Q.

∫cos2x-cos2θcosx-cosθdx=

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a

2(sinx+xcosθ)+C

b

2(sinx-xcosθ)+C

c

2(sinx+2xcosθ)+C

d

2(sinx-2xcosθ)+C

answer is A.

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Detailed Solution

∫cos2x-cos2θcosx-cosθdx=∫(2cos2x-1)-(2cos2θ-1)cosx-cosθdx=2∫cos2x-cos2θcosx-cosθdx=2∫(cosx+cosθ)+C = 2∫cosxdx+∫cosθ dx  =2(sinx+cosθ. x)+C
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∫cos2x-cos2θcosx-cosθdx=