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Q.

∫cos(x−a)cos(x−b)  dx=

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a

xcos(b−a)−sin(b−a)log|sec(x−b)|+c

b

xcos(b−a)+sin(b−a)log|sec(x−b)|+c

c

xcos(b+a)−sin(b+a)log|sec(x+b)|+c

d

xcos(b+a)−sin(b+a)log|sec(x−b)|+c

answer is A.

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Detailed Solution

∫cos(x−b+b−a)cos(x−b) dx  =∫cos(x−b)cos(b−a)−sin(x−b)sin(b−a)cos(x−b) dx =∫cos(b−a) dx-sin(b−a)∫tanx-b dx=xcos(b−a)−sin(b−a)log|sec(x−b)|+C
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