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Q.

∫0π(cos x + | cos x |)dx=

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a

2

b

0

c

1

d

12

answer is A.

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Detailed Solution

∫0πCos x+|Cos x|dx =∫0πCos x dx+∫0π/2|Cos x|dx+∫π/2π|Cos x|dx =(Sin x)0π+(Sin x)0π/2−(Sin x)π/2π =0+(1−0)−(0−1)=2
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