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(1cosx)cosec2xdx is equal to

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a
tan⁡x+C
b
tan⁡x2+C
c
12tan⁡x2+C
d
None of these

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detailed solution

Correct option is B

∫(1−cos⁡x)cosec2⁡xdx=∫cosec2⁡xdx−∫cosec2⁡xcos⁡xdx=cot⁡x−∫cosec⁡xcot⁡xdx =−cot⁡x+cosec⁡x+C=1−cos⁡xsin⁡x+C =2sin2⁡x22sin⁡x2cos⁡x2+C =tan⁡x2+C


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