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$\int \frac{1}{1 + \cos x} d x =$

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tanx2+c

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secx2tanx2+c

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Correct option is A

∫11+cos⁡xdx=∫12cos2⁡x2dx=12∫sec2⁡x2dx 12tan⁡x212+c=tan⁡x2+c

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∫11+cosxdx=

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$\int \frac{1}{1 + \cos x} d x =$