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∫0π 1+ cos 2x2 dx=

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a

1

b

2

c

2

d

0

answer is B.

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Detailed Solution

∫0π2Cos2x2dx=∫0π|Cos x|dx =∫0π/2Cos x dx+∫π/2π−Cos x dx =(Sin x)0π2−(Sin x)π/2π =1−(0−1)=2

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∫0π 1+ cos 2x2 dx=