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0πcos2x+12dx is equal to

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a
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b
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c
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d
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detailed solution

Correct option is C

∫0π cos⁡2x+12dx=∫0π cos2xdx=∫0π |cos⁡x|dx=∫0π/2 cos⁡xdx−∫π/2π cos⁡xdx=2


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