∫cosx−1sinx+1exdx is equal to
excosx1+sinx+C
C−exsinx1+sinx
C−ex1+sinx
C−excosx1+sinx
∫cosx−1sinx+1exdx=∫cosx1+sinxexdx−∫11+sinxexdx=(cosx)ex1+sinx−∫−(1+sinx)sinx−cos2x(1+sinx)2exdx−∫exsinx+1dx+C =excosx1+sinx+∫11+sinxexdx−∫ex1+sinxdx+C=excosx1+sinx+C