∫cos⁡x−sin⁡x8−sin⁡2xdx=asin−1⁡sin⁡x+cos⁡xb+c where c is constant of integration, then the ordered pair a,b=

∫cos⁡x−sin⁡x8−sin⁡2xdx=∫cos⁡x−sin⁡x9−(sin⁡x+cos⁡x)2dx let sin⁡x+cos⁡x=t(cos⁡x−sin⁡x)dx=dt=∫dt9−t2=sin−1⁡t3+c=sin−1⁡sin⁡x+cos⁡x3+cHence, a,b=1,3