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Q.

∫cosx+xsinxx(x+cosx)dx=ln|f(x)|+c

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a

x+cosx

b

x+cosxx

c

xx+cosx

d

x(x+cosx)

answer is C.

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Detailed Solution

∫cosx+xsinxx(x+cosx)dx=∫cosx+x+xsinx−xx(x+cosx)dx ∫cosx+xx(x+cosx)−x(1−sinx)x(x+cosx)dx =∫1x−1−sinxx+cosxdx=ln|x|−ln|x+cosx|+c =ln|xx+cosx|+c
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