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Q.

∫cosec2 ⁡x−2005cos2005⁡ xdx

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a

cot ⁡x(cos⁡ x)2005+C

b

tan ⁡x(cos ⁡x)2005+

c

−tan⁡ x(cos ⁡x)2005+C

d

−cot ⁡x(cos ⁡x)2005+C

answer is D.

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Detailed Solution

I=∫(cos ⁡x)−2005cosec2⁡ x dx−2005∫dxcos2005 ⁡xI=(cos ⁡x)−2005(−cot⁡x)−∫(−2005)(cos ⁡x)−2006   (−sin ⁡x)(−cot⁡x)dx−2005∫dxcos2005⁡ x   I=−cot ⁡x(cos⁡ x)2005+C
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