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cotexcosec2exexdx is equal to 

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a
−2cotex+C
b
2cotex+C
c
−12cotex2+C
d
12cotex+C

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detailed solution

Correct option is C

Let I=∫cot⁡ex⋅cos⁡ec2ex⋅exdx Let ex=yexdx=dyI=∫cot⁡y⋅cos⁡ec2ydy Put cot⁡y=zcos⁡ec2ydy=−dzI=∫z⋅(−dz)=−z22+C=−12(cot⁡y)2+C=−12cot⁡ex2+C


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