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$(1 - \cot 1^{o}) (1 - \cot 2^{o}) (1 - \cot 3^{o}) ............... (1 - \cot 44^{o}) = 2^{n}, t h e n n =$

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Correct option is B

If A+B=π4 then (1-cotA)(1-cotB)=2Now 1-cot1°1-cot2°1-cot3°………..1-cot43°1-cot44°=2n⇒1-cot1°1-cot44°1-cot2°1-cot43°....1-cot22°1-cot23°=2n⇒222=2n⇒n=22

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1−cot1o1−cot2o1−cot3o...............1−cot44o=2n, then n=

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$(1 - \cot 1^{o}) (1 - \cot 2^{o}) (1 - \cot 3^{o}) ............... (1 - \cot 44^{o}) = 2^{n}, t h e n n =$