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1−cot1o1−cot2o1−cot3o...............1−cot44o=2n, then n=

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a

11

b

22

c

44

d

22

answer is B.

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Detailed Solution

If A+B=π4 then (1-cotA)(1-cotB)=2Now 1-cot1°1-cot2°1-cot3°………..1-cot43°1-cot44°=2n⇒1-cot1°1-cot44°1-cot2°1-cot43°....1-cot22°1-cot23°=2n⇒222=2n⇒n=22

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