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cot3xcosec8x  dx

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a
sin6x6−sin8x8+C
b
sin6x6+sin8x8+C
c
cos6x6−cos8x8+C
d
cos6x6+cos8x8+C

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detailed solution

Correct option is A

cosec⁡x=t⇒(cosec⁡xcot⁡x)dx=−dt∫t2−1(−dt)t9=−∫1t7dt+∫1t9dt=16t6−18t8+C


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