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cot2xcosec4x  dx

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a
−cot3x3+cot5x5+C
b
−cot3x3−cot5x5+C
c
−tan3x3+tan5x5+C
d
−cot3x2+cot4x4+C

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detailed solution

Correct option is B

put  cot⁡x=t⇒cos⁡ec2xdx=−dt∫−t2−t4dt=−t33−t55+C


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