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Q.

∫cotx cot(2400−x) cot(2400+x)dx

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a

−13log (sin3x)+c

b

13log (sin3x)

c

13log (sin3x)+C

d

13log (cosec3x)

answer is A.

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Detailed Solution

We know that tan⁡xtan⁡240∘−xtan⁡240∘+x=tan⁡3x∫cot⁡xcot⁡(240−x)cot⁡(240+x)dx=∫cot⁡3xdx=13log⁡(sin⁡3x)+C
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