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$\int \cot x \cot (240^{0} - x) \cot (240^{0} + x) d x$

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−13log (sin3x)+c

13log (sin3x)

13log (sin3x)+C

13log (cosec3x)

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detailed solution

Correct option is A

We know that tan⁡xtan⁡240∘−xtan⁡240∘+x=tan⁡3x∫cot⁡xcot⁡(240−x)cot⁡(240+x)dx=∫cot⁡3xdx=13log⁡(sin⁡3x)+C

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∫cotx cot(2400−x) cot(2400+x)dx

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$\int \cot x \cot (240^{0} - x) \cot (240^{0} + x) d x$