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Q.

∫cot4⁡ysin2⁡ydy is equal to

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a

−15coty5+C

b

15coty5+C

c

5coty5+C

d

−5coty5+C

answer is A.

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Detailed Solution

Let I=∫cot4⁡ysin2⁡ydyI=∫(coty)4cosec2y dy Put cot⁡y=t⇒cosec2⁡ydyI=∫t4(−dt)I=−t55+CI=−15(cot⁡y)5+C
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