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$\int \frac{\cot^{4} y}{\sin^{2} y} d y is equal to$

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−15coty5+C

15coty5+C

5coty5+C

−5coty5+C

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detailed solution

Correct option is A

Let I=∫cot4⁡ysin2⁡ydyI=∫(coty)4cosec2y dy Put cot⁡y=t⇒cosec2⁡ydyI=∫t4(−dt)I=−t55+CI=−15(cot⁡y)5+C

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∫cot4⁡ysin2⁡ydy is equal to

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$\int \frac{\cot^{4} y}{\sin^{2} y} d y is equal to$