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$\int_{0}^{1} \frac{d x}{x + \sqrt{x}}$

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Correct option is B

∫01 dxx(x+1) put x+1=t=∫12 2dtt diff⇒12xdx=dt=2(log⁡t)2 LLt=1ULt=2=2[log⁡2−log⁡1] =2log⁡2

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$\int_{0}^{1} \frac{d x}{x + \sqrt{x}}$