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Q.

∫dxx154+x4512

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a

1+x4/5+c

b

521+x4/5+c

c

x4/5(1+x4/5)1/2+c

d

251+x4/5+c

answer is B.

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Detailed Solution

∫dxx154+x4512 =∫5dt4t12 Let 4+x45=t⇒4/5x1/5dx=dt                               =54t×2+C =52×1+x4512+C
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