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dxx154+x4512

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a
1+x4/5+c
b
521+x4/5+c
c
x4/5(1+x4/5)1/2+c
d
251+x4/5+c

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detailed solution

Correct option is B

∫dxx154+x4512 =∫5dt4t12 Let 4+x45=t⇒4/5x1/5dx=dt                               =54t×2+C =52×1+x4512+C


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