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Q.

∫dxx2(1+x5)45=

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a

-(1+x5)155x+c

b

(1+x5)155x+c

c

-(1+x5)15x+c

d

(1+x5)15x+c

answer is C.

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Detailed Solution

I=∫dxx21+x545​   = ∫dxx61x5+145 Let t=1+1x5⇒dt=−5dxx6∴I=−15∫dtt4/5        =−t1/5+C        =−1+1x515+C       =−x5+115x+C
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