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dxx2(1+x5)45=

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a
-(1+x5)155x+c
b
(1+x5)155x+c
c
-(1+x5)15x+c
d
(1+x5)15x+c

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detailed solution

Correct option is C

I=∫dxx21+x545​   = ∫dxx61x5+145 Let t=1+1x5⇒dt=−5dxx6∴I=−15∫dtt4/5        =−t1/5+C        =−1+1x515+C       =−x5+115x+C


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