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Q.

∫dxx2+x−2 is equal to

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a

log2x+1+x2+x+2+c

b

log2x+1+x2+x−2+c

c

log2x+1+2x2+x+2+c

d

log2x+1+x2+x+1+c

answer is B.

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Detailed Solution

I=∫dxx+122−14−2=∫dxx+122−322I=log⁡x+12+x+122−322+cI=log⁡2x+12+x2+x−2+c=log2x+1+x2+x−2+c
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