∫dx2−3x−x2=(fog)(x)+C then
f(x)=sin−1x,g(x)=2x−317
∫(x)=tan−1x,g(x)=2x+317
f(x)=sin−1x,g(x)=2x+317
none of these
∫dx2−3x−x2=∫dx−x2+3x−2=∫dx−(x+3/2)2−17/4=∫dx17/4−(x+3/2)2=sin−1x+3/217/4+C=sin−12x+317+C
Therefore g(x)=2x+317 and f(x)=sin−1x