∫dxcosx+3sinx is equal to
12logtanx2+π12+C
12logtanx2−π12+C
logtanx2+π12+C
logtanx2−π12+C
Now,
∫dxcosx+3sinx=∫dx212cosx+32sinx=12∫secx−π3dx=12logtanx2−π6+π4+C=12logtanx2+π12+C