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dxcosx+3sinx is equal to

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a
12log⁡tan⁡x2+π12+C
b
12log⁡tan⁡x2−π12+C
c
log⁡tan⁡x2+π12+C
d
log⁡tan⁡x2−π12+C

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detailed solution

Correct option is A

Now,∫dxcos⁡x+3sin⁡x=∫dx212cos⁡x+32sin⁡x=12∫sec⁡x−π3dx=12log⁡tan⁡x2−π6+π4+C=12log⁡tan⁡x2+π12+C


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