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33dx1+ex1+x2 is equal to

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a
π3
b
π6
c
π4
d
π

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detailed solution

Correct option is A

I=∫−33 dx1+ex1+x2 Here, f(x)=11+ex1+x2⇒f(−x)=11+e−x1+(−x)2=ex1+ex1+x2  [using property ∫−aa f(x)dx=∫0a {f(x)+f(−x)}dx∫−33 dx1+ex1+x2=∫03 11+ex1+x2+ex1+ex1+x2dxso, I=∫03 dx1+x2=tan−1⁡x03=π3


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