First slide
Methods of integration
Question

dxa2sin2x+b2cos2x is equal to 

Easy
Solution

dxa2sin2x+b2cos2x=sec2xdxa2tan2x+b2=1a2dtt2+ba2

 wheret=tanx=1a2abtan1tb/a+C=1abtan1a(tanx)b+C

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