∫dxsinx−cosx+2 is equal to
−12tanx2+π8+C
12tanx2+π8+C
12cotx2+π8+C
−12cotx2+π8+C
∫dxsinx−cosx+2=∫dxsinx22−cosx22+2=∫dx2sinxsinπ4−cosxcosπ4+1=12∫dx1−cosx+π4=12∫dx1−cos2x2+π8=12∫dx2sin2x2+π8=122∫cosec2x2+π8dx=−122⋅−cotx2+π812+C=12cotx2+π8+C