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dx925x2 is equal to 

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a
sin−1⁡5x3+C
b
32sin−1⁡5x3+C
c
15sin−1⁡5x3+C
d
None of these

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detailed solution

Correct option is C

∫dx9−25x2=∫dx25352−x2=15∫dx352−x2                         =15sin−1⁡x3/5+C∵∫dxa2−x2=sin−1⁡xa                          =15sin−1⁡5x3+C


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