First slide
Methods of integration
Question

dxa2+x23/2 is equal to

Easy
Solution

I=dxa2+x23/2

put , x=atanθdx=asec2θdθ

 I=asec2θa2+a2tan2θ3/2=asec2θa3sec2θ3/2 I=1a2secθ=1a2cosθdθ=1a2sinθ+C =xa2x2+a21/2+C

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