∫dxa2+x23/2 is equal to
xa2+x21/2+C
xa2a2+x21/2+C
1a2a2+x21/2+C
None of these
I=∫dxa2+x23/2
put , x=atanθ⇒dx=asec2θdθ
∴ I=∫asec2θa2+a2tan2θ3/2dθ=∫asec2θa3sec2θ3/2dθ⇒ I=1a2∫dθsecθ=1a2∫cosθdθ=1a2sinθ+C⇒ =xa2x2+a21/2+C