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$\int \frac{dx}{(x + 3)^{15 / 16} (x - 4)^{17 / 16}}$ is equal to

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x+3x−4116+C

−167x+3x−4116+C

165x−4x+3116+C

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detailed solution

Correct option is B

I=∫dx(x+3)1516(x−4)1716=∫dxx+3x−41516(x−4)2 Put x+3x−4=t⇒(x−4)−(x+3)(x−4)2dx=dt⇒dx(x−4)2=dt−7So, I=−17∫dtt1516=−17∫t−1516dt=−167t116+C=−167x+3x−41/16+C

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∫dx(x+3)15/16(x−4)17/16 is equal to

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$\int \frac{dx}{(x + 3)^{15 / 16} (x - 4)^{17 / 16}}$ is equal to