∫dx(x+2)x2+1 is equal to
15log|x+2|−110logx2+1+25tan−1x+C
log|x+2|+110logx2+1+15tan−1x+C
5log|x+2|+10logx2+1+tan−1x+C
None of the above
Let,
1(x+2)x2+1=Ax+2+Bx+Cx2+1⇒1=Ax2+1+(Bx+C)(x+2)
Put x = -2,weget A=15
Now, comparing the coefficients of x2 and constant term, we get
0=A+Band 1=A+2C⇒B=−15,C=25so,I=15∫dxx+2−15∫xx2+1dx+25∫dxx2+1=15log|x+2|−110logx2+1+25tan−1x+C