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dxx2+2x+2 is equal to 

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a
log∣(x+1)+x2+2x+2∣+C
b
log∣x+x2+2x+2∣+C
c
log⁡x+1−x2+2x+2+C
d
None of the above

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detailed solution

Correct option is A

Let =∫dxx2+2x+2=∫dxx2+2x+1+1=∫1(x+1)2+(1)2dx               (let x+1=t)⇒dx=dt∴ I=∫dtt2+1=log⁡t+t2+1+C ∵∫dxx2+a2=log⁡x+x2+a2=log⁡(x+1)+(x+1)2+1+C=log⁡(x+1)+x2+2x+2+C


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