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Q.

∫dx8+3x−x2 is equal to

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a

23sin−1⁡2x−141+C

b

32sin−1⁡2x−341+C

c

141sin−1⁡2x−341+C

d

sin−1⁡2x−341+C

answer is D.

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Detailed Solution

LetI=∫18+3x−x2dx=∫18−x2−3x+322−322dx=∫18−x−322−94dx=∫18+94−x−322dx=∫14122−x−322dxLet x−32=t⇒dx=dt∴I=∫14122−t2dt=sin−1⁡t412+C∵∫dxa2−x2=sin−1⁡xa=sin−1⁡x−32412+C=sin−1⁡2x−341+C∵t=x−32
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