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$\int_{e^{- 1}}^{e^{2}} | \frac{\ln x}{x} | d x =$

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detailed solution

Correct option is B

I=∫e−1e2|lnxx|dx=∫e−11−lnxxdx+∫1e2lnxxdx =−12(lnx)2|1e−1+12(lnx)2|1e2 =12+12×4=52

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